Maximum unique number from number stream

Maximum unique number from number stream

A question asked in Knowlarity , Gurgaon Interview :

You have a stream of numbers. At any time , find the maximum and the unique number at any time.
I/P: 5 6 7 7 6

O/p:5 6 7 6 5

Avaialble at https://www.geeksforgeeks.org/knowlarity-interview-experience/

Solution is as follows in C++11 :

#include<bits/stdc++.h>
#include <unordered_map>
using namespace std;
void findMaxArray(int arr[],int n)
{
    int max = arr[0];
    if(n==0)
    {
        cout << -1;
        return;
    }
    unordered_map< int ,int> s;
    s.insert(std::make_pair(arr[0],0));
    int maxV[n] ;
    maxV[0]=arr[0];
    cout << maxV[0] << “\t”;
    for (int i=1; i<n; i++)
    {
        if (s.find(arr[i]) == s.end())
        {
            if(arr[i] > maxV[i-1])
                maxV[i]=arr[i];
            s.insert(std::make_pair(arr[i],i));
            cout << maxV[i] << “\t” ;
        }
        else
        {
           int index = s[arr[i]];
            maxV[index]=-1;
           int j=i-1;
           for(; j >=0 ; j–)
            {
                if(maxV[j] != arr[i])
                {
                    if(maxV[j] != -1)
                    {
               maxV[i]=maxV[j];
                        cout << maxV[j] << “\t”;
                        break;
                    }
                }
                else
                    maxV[j]=-1;
            }
            if(j == -1)
            {
                maxV[i] = -1;
                cout << -1 << “\t”;
            }
        }
    }
}
int main()
{
    int arr[] = {5,6,7,7,6};
    int n = sizeof(arr)/sizeof(int);
    findMaxArray(arr, n);
    return 0;
}

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