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Codechef 2017 January Challenge RECTANGL

RECTANGL

You are given four integers a, b, c and d. Determine if there’s a rectangle such that the lengths of its sides are a, b, c and d (in any order).

Input

• The first line of the input contains a single integer T denoting the number of test cases. The description of T test cases follows.
• The first and only line of each test case contains four space-separated integers a, b, c and d.

Output

For each test case, print a single line containing one string "YES" or "NO".

Constraints

• 1 ≤ T ≤ 1,000
• 1 ≤ a, b, c, d ≤ 10,000

Subtasks

Subtask #1 (100 points): original constraints

Example

<b>Input:</b>

3
1 1 2 2
3 2 2 3
1 2 2 2

<b>Output:</b>

YES
YES
NO

Solution in Java:

Make sure both pairs are equal in value.

import java.io.*;
import java.util.StringTokenizer;
 class RECTANGL {

    public static void main(String[] args) throws IOException
    {
        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
        BufferedWriter bw = new BufferedWriter(new OutputStreamWriter(System.out));
        int t = Integer.parseInt(br.readLine());
        while(t-- >0)
        {
            StringTokenizer str = new StringTokenizer(br.readLine()," ");
            int a = Integer.parseInt(str.nextToken());
            int b = Integer.parseInt(str.nextToken());
            int c = Integer.parseInt(str.nextToken());
            int d = Integer.parseInt(str.nextToken());

            if(a == b )
            {
                if(c ==  d)
                {
                    bw.write("YES"+ "\n");
                    bw.flush();
                }
                else
                {
                    bw.write("NO"+ "\n");;
                    bw.flush();
                }

            }
            else if(a==c)
            {
                if(b ==  d)
                {
                    bw.write("YES"+ "\n");
                    bw.flush();
                }
                else
                {
                    bw.write("NO"+ "\n");
                    bw.flush();
                }

            }
            else if(a==d)
            {
                if(b ==  c)
                {
                    bw.write("YES"+ "\n");
                    bw.flush();
                }
                else
                {
                    bw.write("NO"+ "\n");
                    bw.flush();
                }

            }
            else
            {
                bw.write("NO"+ "\n");
                bw.flush();
            }

        }

    }
}

Another Question from same challenge:

STRING MERGING CODECHEF JANUARY CHALLENGE